50 lines
2.6 KiB
JavaScript
50 lines
2.6 KiB
JavaScript
// 宗师顶（B·职业层）单测 —— 2026-07-21 立。
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// 守：①double-witness 自检(done 必双证) ②归类有限集 ③唐学者→国子祭酒双证在 ④noTrack 诚实 ⑤查不实标待补不编。
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// 跑：node --test test/zongshi.test.js
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import test from 'node:test';
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import assert from 'node:assert/strict';
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import { GUDAI_LEI, MODERN_TO_GUDAI, classifyProfession, zongshiFor, assertZongshi, ZONGSHI } from '../src/zongshi.js';
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test('①宗师顶双证自检 CLEAN（done 的每条都两证齐全）', () => {
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assert.deepEqual(assertZongshi(), [], 'done:true 的宗师顶必须双证齐全');
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});
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test('②归类：预设类走映射、自由文本走关键词、命不中返 null（不硬猜）', () => {
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assert.equal(classifyProfession('中医大夫', 'health').lei, 'yi', '预设 health→医');
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assert.equal(classifyProfession('国画家', 'art').lei, 'yishu', '预设 art→艺');
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assert.equal(classifyProfession('针灸推拿').lei, 'yi', '自由文本关键词→医');
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assert.equal(classifyProfession('书法老师').lei, 'yishu', '自由文本→艺');
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assert.equal(classifyProfession('高中语文老师').lei, 'wen', '自由文本→文');
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assert.equal(classifyProfession('外卖调度不知道啥').lei, null, '归不了 → null，交给 AI/用户，不硬猜');
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});
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test('③唐·学者宗师顶=国子监祭酒·从三品，两史互证', () => {
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const z = zongshiFor('wen', 'tang');
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assert.ok(z?.done, '唐学者宗师顶已双证上线');
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assert.equal(z.title, '国子监祭酒');
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assert.equal(z.grade, '从三品');
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assert.match(z.source, /新唐书/);
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assert.match(z.source2, /旧唐书/);
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assert.ok(z.quote.includes('從三品') && z.quote2.includes('從三品'), '两证都逐字含「從三品」');
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});
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test('④noTrack 诚实：商无正经仕途巅峰，不编假官', () => {
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const z = zongshiFor('shang', 'tang');
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assert.ok(z?.noTrack, '商→noTrack');
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assert.ok(!z.title, 'noTrack 绝不带 title（不编假官）');
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});
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test('⑤查不实标待补：唐·医宗师顶未双证 ⇒ done:false，不当真数据发', () => {
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const z = zongshiFor('yi', 'tang');
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assert.equal(z?.done, false, '未双证的必须 done:false');
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assert.ok(z.note, '待补条必须写明为什么待补');
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});
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test('⑥有限集：古代类是有限的几类，现代类全映射到其中（other 除外）', () => {
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const leiIds = new Set(GUDAI_LEI.map((l) => l.id));
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for (const [modern, lei] of Object.entries(MODERN_TO_GUDAI)) {
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if (lei === null) continue; // other 待分类
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assert.ok(leiIds.has(lei), `现代类 ${modern} 映到的 ${lei} 必须是有限古代类之一`);
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}
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});
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