53 lines
2.9 KiB
JavaScript
53 lines
2.9 KiB
JavaScript
// 改命打卡 单测 —— 2026-07-21 立（老板："要按天或周持续有改变才能改命"）。
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// 锁死：①连续打卡 streak 累加、幂等 ②断了衰减(归 0) ③连续 3 期点亮 ④综合指标按方向数等比守门。
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import test from 'node:test';
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import assert from 'node:assert/strict';
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import { checkin, boardState, gaimingPoints, GAIMING_ITEMS } from '../src/gaiming.js';
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const D = (s) => new Date(s + 'T12:00:00Z'); // 固定时间,纯函数可测
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test('①日项连续打卡 streak 累加;同一天重复打卡幂等(不重复加)', () => {
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let g = {};
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g = checkin(g, 'read', D('2026-07-19'));
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assert.equal(g.read.streak, 1, '第1天 → 1');
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g = checkin(g, 'read', D('2026-07-19')); // 同一天再打
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assert.equal(g.read.streak, 1, '★ 同一天重复打卡幂等,仍 1');
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g = checkin(g, 'read', D('2026-07-20'));
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g = checkin(g, 'read', D('2026-07-21'));
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assert.equal(g.read.streak, 3, '连续 3 天 → 3');
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});
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test('②断了就衰减:隔一天没打,boardState 里 streak 归 0、不点亮', () => {
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let g = {};
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for (const day of ['2026-07-17', '2026-07-18', '2026-07-19']) g = checkin(g, 'read', D(day));
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assert.equal(boardState(g, D('2026-07-19'))[0].streak, 3, '当天看:连 3');
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// 到 21 号才看(19 打的,20 没打 → 断了)
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const stale = boardState(g, D('2026-07-21')).find((s) => s.id === 'read');
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assert.equal(stale.streak, 0, '★ 断了 → 衰减归 0(逼你持续)');
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assert.equal(stale.lit, false, '断了不点亮');
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});
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test('③连续 3 期点亮该项;②周项按周算', () => {
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let g = {};
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for (const day of ['2026-07-07', '2026-07-14', '2026-07-21']) g = checkin(g, 'social', D(day)); // 三个连续周二
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const s = boardState(g, D('2026-07-21')).find((x) => x.id === 'social');
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assert.equal(s.streak, 3, '连续 3 周 → 3');
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assert.equal(s.lit, true, '★ 连 3 周 → 点亮');
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});
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test('④方向扩容后门槛等比提高：两项刚点亮不够，持续多项才抬一档', () => {
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let g = {};
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// read 连 3 天 + earlyrise 连 3 天：综合池只有 2 分，不因可选方向变多而让改命变松。
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for (const day of ['2026-07-19', '2026-07-20', '2026-07-21']) { g = checkin(g, 'read', D(day)); g = checkin(g, 'earlyrise', D(day)); }
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assert.equal(gaimingPoints(g, D('2026-07-21')), 0, '两项刚点亮仍未达到等比门槛');
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// 所有日项连续 7 天，每项进入「稳住」档，足以跨过第一档门槛。
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g = {};
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const daily = GAIMING_ITEMS.filter((item) => item.cadence === 'day');
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for (const day of ['2026-07-15', '2026-07-16', '2026-07-17', '2026-07-18', '2026-07-19', '2026-07-20', '2026-07-21']) {
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for (const item of daily) g = checkin(g, item.id, D(day));
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}
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assert.equal(gaimingPoints(g, D('2026-07-21')), 2, '多方向持续到稳住档 → 后天改命抬一档');
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assert.ok(GAIMING_ITEMS.length >= 6, '打卡项日+周至少 6 项(可选项多)');
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});
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